After we learned about balanced wye-wye connection, we will learn about the most practical three-phase system. We usually use a balanced wye-delta connection.

**Contents**show

As it implies, a balanced Y-∆ system has a balanced Y-connected source supplying a balanced ∆-connected load.

*Make sure to read what is three-phase circuit first.*

Since both the three-phase source and the three-phase load can be either wye- or delta-connected, we have four possible connection :

- Balanced wye-wye connection (i.e., Y-connected source with a Y-connected load).
- Balanced wye-delta connection.
- Balanced delta-delta connection.
- Balanced delta-wye connection.

## Balanced Wye-Delta Connection

We can see the example of a balanced Y-∆ system in Figure.(1), where the source is Y-connection and the load is ∆-connection.

Figure 1. Balanced Y-∆ connection |

There is no neutral point from source to load for this connection. Assuming the positive sequence, the phase voltages are again

(1) |

The line voltages are

(2) |

Hence, it shows us that the voltage across the load impedances for this system is equal to the line voltages using this connection.

From these voltages, we can obtain the phase currents as

(3) |

These currents have the same magnitude but are out of phase with each other by 120◦.

Another way to get these phase currents is to apply KVL. For example, applying KVL around loop *aABbna* gives

(4) |

which is the same as Equation.(3). This is the more general way of finding the phase currents.

The line currents are obtained from the phase currents by applying KCL at nodes A, B, and C. Thus,

(5) |

Since **I**_{CA} = **I**_{AB}∠−240◦,

(6) |

showing that the magnitude **I**_{L} of the line current is √3 times the magnitude **I**_{p} of the phase current, or

(7) |

where

(8) |

and

(9) |

Also, the line currents lag the corresponding phase currents by 30◦, assuming the positive sequence.

Figure.(2) is a phasor diagram illustrating the relationship between the phase and line currents.

Figure 2. Phasor diagram illustrating the relationship between phase and line currents |

An alternative way of analyzing the Y-∆ circuit is to transform the ∆-connected load to an equivalent Y-connected load.

Using the ∆-Y transformation formula,

(10) |

After this transformation, we now have a Y-Y system as in the balanced wye-wye connection.

We can redraw the three-phase Y-∆ system in Figure.(1) to a single-phase equivalent circuit in Figure.(2). This allows us to calculate only the line currents.

The phase currents are obtained using Equation.(7) and utilizing the fact that each of the phase currents leads the corresponding line current by 30◦.

Figure 3. A single-phase equivalent circuit of a balanced Y-∆ circuit |

## Balanced Wye-Delta Connection Example

For better understanding let us review the example below:

1. A balanced *abc*-sequence Y-connected source with **V**_{an} = 100∠10◦ V is connected to a ∆-connected balanced load (8 + j4) Ω per phase.

We can get the phase and line currents.

*Solution:*

We can solve this problem in two ways.

**Method 1**

The load impedance is

If the phase voltage **V**_{an} = 100∠10◦, then the line voltage is

or

The phase currents are

The line currents are

**Method 2**

Alternatively, using single-phase analysis,

as above. Other line currents are obtained using the *abc* phase sequence.