If you have read the previous post about what is an inductor, let us proceed to the next level, what is the inductance formula circuits.
Now that the inductor has been added to our list of passive elements, it is necessary to extend the powerful tool of series-parallel combination. We need to know how to find the equivalent inductance of a series-connected or parallel-connected set of inductors found in practical circuits.
Consider a series connection of N inductors, as shown in Figure.(1a), with the equivalent circuit shown in Figure.(1b).
The inductors have the same current through them. Applying KVL to the loop,
The equivalent inductance of series-connected inductors is the sum of the individual inductances.
We now consider a parallel connection of N inductors, as shown in Figure.(2a), with the equivalent circuit in Figure.(2b). The inductors have the same voltage across them. Using KCL,
The initial current i(t0) through Leq at t
According to Equation.(6),
The equivalent inductance of parallel inductors is the reciprocal of the sum of the reciprocals of the individual inductances.
Note that the inductors in parallel are combined in the same way as resistors in parallel.
For two inductors in parallel (N = 2), Equation.(6) becomes
Inductance Formula Circuits Examples
1. Find the equivalent inductance of the circuit shown in Figure.(3).
The 10-H, 12-H, and 20-H inductors are in series; thus, combining them gives a 42-H inductance. This 42-H inductor is in parallel with the 7-H inductor so that they are combined, to give
This 6-H inductor is in series with the 4-H and 8-H inductors. Hence,
2. For the circuit in Figure.(4),
i(t) = 4(2 − e−10t) mA. If i2(0) = −1 mA, find:
(b) v(t), v1(t), and v2(t);
(c) i1(t) and i2(t).
(a) From i(t) = 4(2 − e−10t) mA, i(0) = 4(2 − 1) = 4 mA.
Since i = i1 + i2,
(b) The equivalent inductance is
Since v = v1 + v2,
(c) The current i1 is obtained as
Note that i1(t) + i2(t) = i(t).