{"id":16,"date":"2021-07-24T13:50:00","date_gmt":"2021-07-24T13:50:00","guid":{"rendered":""},"modified":"2025-01-29T05:37:34","modified_gmt":"2025-01-29T05:37:34","slug":"rangkaian-ac-op-amp","status":"publish","type":"post","link":"https:\/\/wiraelectrical.com\/id\/rangkaian-ac-op-amp\/","title":{"rendered":"Rangkaian AC Op Amp"},"content":{"rendered":"\n
Op Amp dapat juga dianalisa ketika terhubung dengan sumber ac. Ide dasarnya adalah sama dengan beberapa teknik lain, antara lain :<\/div>\n
\u00a0<\/div>\n
    \n
  1. Transformasikan rangkaian ke domain fasor atau frekuensi<\/li>\n
  2. Selesaikan masalah menggunakan teknik analisa rangkaian\n
      \n
    1. Kirchoff<\/li>\n
    2. Nodal<\/span><\/li>\n
    3. \n
      Mesh<\/div>\n<\/li>\n
    4. \n
      Superposisi<\/div>\n<\/li>\n
    5. \n
      Transformasi sumber<\/div>\n<\/li>\n
    6. \n
      Thevenin dan Norton<\/div>\n<\/li>\n<\/ol>\n<\/li>\n
    7. Transformasikan lagi hasilnya ke domain waktu.<\/li>\n<\/ol>\n\n\n\n

      Baca juga : jenis relay<\/a><\/p>\n\n\n\n

      Rangkaian AC Op Amp<\/h2>\n\n\n\n
      Tolong ingat, kita akan menggunakan op amp ideal untuk mempermudah pemahaman. Perhatikan kunci dari proses analisa rangkaian op amp, antara lain :<\/div>\n
      \u00a0<\/div>\n
        \n
      1. Tidak ada arus yang masuk di semua terminal input<\/li>\n
      2. Tegangan pada terminal input adalah nol<\/li>\n<\/ol>\n

        \u00a0<\/p>\n

        Mari kita simak contoh di bawah :<\/div>\n
        1. Tentukan\u00a0vo<\/sub>(t)<\/i>\u00a0untuk op amp di Rangkaian.(1a) jika\u00a0vs<\/sub><\/i>\u00a0= 3 cos 1000t V.<\/b><\/div>\n\n\n\n\n
        \"rangkaian<\/a><\/td>\n<\/tr>\n
        Gambar 1. Untuk contoh 1 : (a) rangkaian asal pada domain waktu, (b) domain frekuensinya<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
        Solusi :<\/i><\/u><\/div>\n
        Kita pertama mengubah rangkaian ke domain frekuensi seperti di Gambar.(1b), dimana\u00a0V<\/b>s<\/sub>\u00a0= 3\u22200o<\/sup>,\u00a0\u03c9<\/i>\u00a0= 1000 rad\/s. Menggunakan KCL di node 1 kita peroleh<\/div>\n
        \"rangkaian<\/a><\/div>\n
        atau<\/div>\n\n\n\n\n
        \"rangkaian<\/a><\/td>\n<\/tr>\n
        (1.1)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
        Pada node 2, KCL menghasilkan<\/div>\n
        \"rangkaian<\/a><\/div>\n
        dan menghasilkan<\/div>\n\n\n\n\n
        \"rangkaian<\/a><\/td>\n<\/tr>\n
        (1.2)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
        Substitusi Persamaan.(1.2) ke (1.1) menghasilkan<\/div>\n
        \"rangkaian<\/a><\/div>\n
        Jadi<\/div>\n
        \"rangkaian<\/a><\/div>\n
        \u00a0<\/div>\n
        2. Hitung penguatan (gain) closed loop dan pergeseran fasa untuk rangkaian di Gambar.(2). Anggap\u00a0\u00a0R1<\/sub>\u00a0= R2<\/sub>\u00a0= 10 k\u03a9, C1<\/sub>\u00a0= 2 uF, C2\u00a0<\/sub>= 1 uF, dan\u00a0\u03c9<\/i>\u00a0= 200 rad\/s.<\/b><\/div>\n\n\n\n\n
        \"rangkaian<\/a><\/td>\n<\/tr>\n
        Gambar 2<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
        Solusi :<\/i><\/u><\/div>\n
        Nilai feedback dan impedansi<\/a> inputnya adalah<\/div>\n
        \"rangkaian<\/a><\/div>\n
        Karena rangkaian di Gambar.(2) adalah inverting amplifier atau penguat pembalik, penguat closed loop adalah<\/div>\n
        \"rangkaian<\/a><\/div>\n
        Substitusi nilai yang diperoleh dari R1<\/sub>, R2<\/sub>, C1<\/sub>, C2<\/sub>, dan\u00a0\u03c9<\/i>, kita dapatkan<\/div>\n
        \"rangkaian<\/a><\/div>\n
        Jadi, penguat closed loop adalah 0.434 dan pergeseran fasa adalah 130.6o<\/sup><\/div>\n
        \u00a0<\/div>\n
        For English read\u00a0Op Amp AC Circuits<\/a><\/div>\n\n\n\n

        <\/p>\n","protected":false},"excerpt":{"rendered":"","protected":false},"author":1,"featured_media":254,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[52],"tags":[],"class_list":["post-16","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-rangkaian-analog","resize-featured-image"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/posts\/16","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/comments?post=16"}],"version-history":[{"count":4,"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/posts\/16\/revisions"}],"predecessor-version":[{"id":1999,"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/posts\/16\/revisions\/1999"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/media\/254"}],"wp:attachment":[{"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/media?parent=16"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/categories?post=16"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/wiraelectrical.com\/id\/wp-json\/wp\/v2\/tags?post=16"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}